[转载]程序开发技术交流分享 » Post Topic » java模拟form表单提交图片文件.
这次要和别人开发的服务器端程序接口对接,之前实现的上传文件的方法对方接口无法接收。他们的接口需要类似这样的form提交数据:
<form enctype="multipart/form-data" action=http://url/path method="POST"> <input name="filename” type="file" /> <input type="submit" value="test" /> </form>
解决办法是引入commons-httpclient.jar,下载地址http://hc.apache.org/downloads.cgi,模拟form表单提交数据,代码如下:
File f = new File("device1.png"); PostMethod filePost = new PostMethod( "http://url/path"); Part[] parts = { new FilePart("filename", f) }; filePost.setRequestEntity(new MultipartRequestEntity(parts, filePost .getParams())); HttpClient clients = new HttpClient(); int status = clients.executeMethod(filePost); try { BufferedReader rd = new BufferedReader(new InputStreamReader( filePost.getResponseBodyAsStream(), "UTF-8")); StringBuffer stringBuffer = new StringBuffer(); String line; while ((line = rd.readLine()) != null) { stringBuffer .append(line); } rd.close(); System.out.println("接受到的流是:" + stringBuffer + "—-" + status); } catch (Exception e) { throw new RuntimeException("error”,e); }
解释一下
filePost.setRequestEntity(new MultipartRequestEntity(parts, filePost .getParams()));
设置多媒体参数,作用类似form表单中的enctype=”multipart/form-data” ,
Part[] parts = { new FilePart("filename", f) };
设定参数名称和值,类似form表单中的
try catch块主要是打印服务器端回传的数据。